Example 11
Using the information in Table 8.5.2, predict what will happen in each case involving strong electrolytes. Write the net ionic equation for any reaction that occurs.
- Aqueous solutions of barium chloride and lithium sulfate are mixed.
- Aqueous solutions of rubidium hydroxide and cobalt(II) chloride are mixed.
- Aqueous solutions of strontium bromide and aluminum nitrate are mixed.
- Solid lead(II) acetate is added to an aqueous solution of ammonium iodide.
Given: reactants
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Asked for: reaction and net ionic equation
Strategy:
A Identify the ions present in solution and write the products of each possible exchange reaction.
B Refer to Table 8.2 to determine which, if any, of the products is insoluble and will therefore form a precipitate. If a precipitate forms, write the net ionic equation for the reaction.
Solution:
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A Because barium chloride and lithium sulfate are strong electrolytes, each dissociates completely in water to give a solution that contains the constituent anions and cations. Mixing the two solutions initially gives an aqueous solution that contains Ba2+, Cl−, Li+, and SO42− ions. The only possible exchange reaction is to form LiCl and BaSO4:
B We now need to decide whether either of these products is insoluble. Table 8.2 shows that LiCl is soluble in water (rules 1 and 4), but BaSO4 is not soluble in water (rule 5). Thus BaSO4 will precipitate according to the net ionic equation
(Ba^{2+}(aq) + SO_4^{2-}(aq) rightarrow BaSO_4(s))
Although soluble barium salts are toxic, BaSO4 is so insoluble that it can be used to diagnose stomach and intestinal problems without being absorbed into tissues. An outline of the digestive organs appears on x-rays of patients who have been given a “barium milkshake” or a “barium enema”—a suspension of very fine BaSO4 particles in water.
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A Rubidium hydroxide and cobalt(II) chloride are strong electrolytes, so when aqueous solutions of these compounds are mixed, the resulting solution initially contains Rb+, OH−, Co2+, and Cl− ions. The possible products of an exchange reaction are rubidium chloride and cobalt(II) hydroxide):
B According to Table 8.5.2, RbCl is soluble (rules 1 and 4), but Co(OH)2 is not soluble (rule 5). Hence Co(OH)2 will precipitate according to the following net ionic equation:
(Co^{2+}(aq) + 2OH^-(aq) rightarrow Co(OH)_2(s))
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A When aqueous solutions of strontium bromide and aluminum nitrate are mixed, we initially obtain a solution that contains Sr2+, Br−, Al3+, and NO3− ions. The two possible products from an exchange reaction are aluminum bromide and strontium nitrate:
B According to Table 8.2, both AlBr3 (rule 4) and Sr(NO3)2 (rule 2) are soluble. Thus no net reaction will occur.
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A According to Table 8.2, lead acetate is soluble (rule 3). Thus solid lead acetate dissolves in water to give Pb2+ and CH3CO2− ions. Because the solution also contains NH4+ and I− ions, the possible products of an exchange reaction are ammonium acetate and lead(II) iodide:
B According to Table 8.2, ammonium acetate is soluble (rules 1 and 3), but PbI2 is insoluble (rule 4). Thus Pb(C2H3O2)2 will dissolve, and PbI2 will precipitate. The net ionic equation is as follows:
(Pb^{2+} (aq) + 2I^-(aq) rightarrow PbI_2(s) )
Exercise
Using the information in Table 8.2, predict what will happen in each case involving strong electrolytes. Write the net ionic equation for any reaction that occurs.
- An aqueous solution of strontium hydroxide is added to an aqueous solution of iron(II) chloride.
- Solid potassium phosphate is added to an aqueous solution of mercury(II) perchlorate.
- Solid sodium fluoride is added to an aqueous solution of ammonium formate.
- Aqueous solutions of calcium bromide and cesium carbonate are mixed.
Answer:
- (Fe^{2+}(aq) + 2OH^-(aq) rightarrow Fe(OH)_2(s))
- (2PO_4^{3-}(aq) + 3Hg^{2+}(aq) rightarrow Hg_3(PO_4)_2(s))
- (NaF(s)) dissolves; no net reaction
- (Ca^{2+}(aq) + CO_3^{2-}(aq) rightarrow CaCO_3(s))
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Category: WHICH