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To find the molarity of the NaOH solution, we need to use the definition of mole fraction and the relationship between molarity and density.

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The mole fraction of NaOH (XNaOH) is defined as the moles of NaOH divided by the total moles of all components in the solution. Mathematically, it can be expressed as:

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XNaOH = moles of NaOH / (moles of NaOH + moles of water)

Since water is the only other component in the solution, the mole fraction of water (XH2O) can be calculated as:

XH2O = moles of water / (moles of NaOH + moles of water)

Since the mole fraction of NaOH is given as 0.19, we can write:

0.19 = moles of NaOH / (moles of NaOH + moles of water)

Simplifying this equation, we get:

moles of NaOH = 0.19 * (moles of NaOH + moles of water)

Next, we need to use the relationship between molarity, moles, and volume. Molarity (M) is defined as moles of solute divided by volume of solution in liters. Mathematically, it can be expressed as:

M = moles of solute / volume of solution (in liters)

In this case, the volume of the solution is not given, but we are given the density of the solution, which is 1.133 g/mL. We can use the density to calculate the volume of the solution.

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Density = mass / volume

Since the density is given in g/mL, we need to convert it to g/L to match the units of molarity. We can do this by multiplying the density by 1000.

1.133 g/mL * 1000 mL/L = 1133 g/L

Now we can calculate the volume of the solution using the mass and density:

volume of solution = mass of solution / density

Since the density is given as 1.133 g/mL and the mass is not given, we cannot calculate the exact volume of the solution. However, we can assume a convenient value for the mass, such as 100 g, to illustrate the calculation.

volume of solution = 100 g / 1.133 g/mL = 88.14 mL = 0.08814 L

Finally, we can substitute the values into the molarity equation:

M = moles of NaOH / volume of solution

M = moles of NaOH / 0.08814 L

Since we previously found that moles of NaOH = 0.19 * (moles of NaOH + moles of water), we can substitute this expression into the molarity equation:

M = 0.19 * (moles of NaOH + moles of water) / 0.08814 L

At this point, we have an equation with two variables (moles of NaOH and moles of water) and one equation (0.19 = moles of NaOH / (moles of NaOH + moles of water)). Therefore, we cannot solve for the exact molarity without additional information.

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